Well, I'm going to spend an infinite amount of time traveling the first 500m. Therefore, my speed will be approaching 0m/h. If I maintain that speed, I will also travel the second 500m in forever. But forever twice is still just forever, so I have effectively doubled my speed, just like you wanted me to.
interesting appraoch :)
but I cannot agree with x=2x while x tends to infinity
although they are both infinity, but algerbarically they are bot approaching each other
What's that :)?
oops
Well, I'm going to spend an infinite amount of time traveling the first 500m. Therefore, my speed will be approaching 0m/h. If I maintain that speed, I will also travel the second 500m in forever. But forever twice is still just forever, so I have effectively doubled my speed, just like you wanted me to.
interesting appraoch :)
but I cannot agree with x=2x while x tends to infinity
although they are both infinity, but algerbarically they are bot approaching each other