If you tell me right ans Then you win 10 SBD
First question
Say if (1+3)=4, (2 + 4) = 10, (3 + 5) = 18, then in this section (6 + 8) = how much?
Second question
Now See this picture and ans my question ?
Question : Say,what is the sum of the particular post in the given section ?
I know the first question, it is very easy but I dont understand the second one.
can you try again. I hope you can ans this question.
The first question is 54
(1+3)=4, (2 + 4) = 10, (3 + 5) = 18
If you follow the pattern adding +1 to both number into parenthesis you get:
(1+3)=4, (2 + 4) = 10, (3 + 5) = 18, (4+6) = X, (5+7) = Y, (6+8) = Z
Then, the solution is to take the numbers of a parenthesis and add the solution of the last one.
(2+4)+4 = 10
(3+5)+10 = 18
(4+6)+18 = 28
(5+7)+28 = 40
(6+8)+40 = 54
But the second question... I dont understand.
Gosh! This is so tricky. But I will like to try.
First Question is $32
Second Question is 54 ie 6*9=54.
Happy Sunday.
wrong ans try again.
Question 1
Answer is 54.
Workings
1 + 3 = 4
The formular used to arrive at this is
a + b= ab + a
Now, lets verify.
1 + 3 = 1 *3 + 1= 4
2 + 4 = 2 *4 + 2 =10
3 + 5 = 3 *5 + 3= 18
Now i have verified my formular.
Then
6 + 8 = 6 * 8 + 6 = 54
The answer is 54
.
I dont get the second question.
sorry wrong ans
Second question is 12.
First question is 14.
no. please try again
Question 1
Answer is 54.
Workings
1 + 3 = 4
The formular used to arrive at this is
a + b= ab + a
Now, lets verify.
1 + 3 = 1 *3 + 1= 4
2 + 4 = 2 *4 + 2 =10
3 + 5 = 3 *5 + 3= 18
Now i have verified my formular.
Then
6 + 8 = 6 * 8 + 6 = 54
The answer is 54
.
I dont get the second question.
First question right now ans me second question.
Seriously, I dont understand the second question.
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Question 1: The answer is 54
Workings:
1 + 3 = 4
The formula used to achieve this is:
a + b = ab + a
Now let's verify
1 + 3 = 1×3 +1 = 4
2 + 4 = 2×4 + 2 = 10
3 + 5 = 3×5 + 3 = 18
Then
6 + 8 = 6×8 + 6 = 54
Question 2: What is the sum of the particular post in the given section is 5