If you tell me right ans Then you win 10 SBD

in #puzzle7 years ago

First question

Say if (1+3)=4, (2 + 4) = 10, (3 + 5) = 18, then in this section (6 + 8) = how much?

Second question

Now See this picture and ans my question ?
Question : Say,what is the sum of the particular post in the given section ?

sb.jpg

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I know the first question, it is very easy but I dont understand the second one.

can you try again. I hope you can ans this question.

The first question is 54

(1+3)=4, (2 + 4) = 10, (3 + 5) = 18

If you follow the pattern adding +1 to both number into parenthesis you get:

(1+3)=4, (2 + 4) = 10, (3 + 5) = 18, (4+6) = X, (5+7) = Y, (6+8) = Z
Then, the solution is to take the numbers of a parenthesis and add the solution of the last one.

(2+4)+4 = 10
(3+5)+10 = 18
(4+6)+18 = 28
(5+7)+28 = 40
(6+8)+40 = 54

But the second question... I dont understand.

Gosh! This is so tricky. But I will like to try.
First Question is $32
Second Question is 54 ie 6*9=54.
Happy Sunday.

Question 1
Answer is 54.

Workings
1 + 3 = 4
The formular used to arrive at this is
a + b= ab + a
Now, lets verify.
1 + 3 = 1 *3 + 1= 4
2 + 4 = 2 *4 + 2 =10
3 + 5 = 3 *5 + 3= 18
Now i have verified my formular.

Then
6 + 8 = 6 * 8 + 6 = 54

The answer is 54

.
I dont get the second question.

Second question is 12.
First question is 14.

Question 1
Answer is 54.

Workings
1 + 3 = 4
The formular used to arrive at this is
a + b= ab + a
Now, lets verify.
1 + 3 = 1 *3 + 1= 4
2 + 4 = 2 *4 + 2 =10
3 + 5 = 3 *5 + 3= 18
Now i have verified my formular.

Then
6 + 8 = 6 * 8 + 6 = 54

The answer is 54

.
I dont get the second question.

First question right now ans me second question.

Seriously, I dont understand the second question.

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Question 1: The answer is 54
Workings:
1 + 3 = 4
The formula used to achieve this is:
a + b = ab + a
Now let's verify
1 + 3 = 1×3 +1 = 4
2 + 4 = 2×4 + 2 = 10
3 + 5 = 3×5 + 3 = 18
Then
6 + 8 = 6×8 + 6 = 54

Question 2: What is the sum of the particular post in the given section is 5