Hey! I'm not an expert in maths, but i came up with this.
a) If i understand it right you need to create a function for f/g
f/g = (-3x + 1)/(-5x + 6) = -1 * (3x - 1)/ -1 * (5x - 6) = (3x - 1)/(5x - 6)
This is the simplest form i can get it to.
x can't be equal to 1.2, since then 5 * 1.2 = 6 and 6 - 6 = 0, and you can't divide by 0.
b) If I understand it right, I can answer with an expression
Avg. is: delta y/delta x, so (highest Y - lowest Y)/(highest X - lowest X) = (k(h - 1) - k(-1))/(h -1 - (-1)) = (k(h - 1) - k(-1))/h = (k(h - 1) -1)/h
This is the simplest form i can get it to. h -1 - (-1) is H because: - (-1) is +1 and -1 + 1 is 0, which we can ignore. H can't equal to zero is right as stated in the exercise.
c) If I understand right I can answer with an expression
Same.
Avg. = delta Y / delta X = (g(h) - g(0))/(h - 0) = (g(h) - g(0))/h = (g(h))/(h)
g(0) = 0, this way we can ignore this, because: 0^2 = 0, 0*9 = 0
Sorry if I did something wrong English isn't my main language.
Legend
/ means division - means subtraction * means multiplication + means add delta means it's a differential value (highest value - starting point)
Let me know if this is what you want, or you can't understand this!
@shankarchandraray I can solve your problem...let us help each other.....I m done.....your turn now
YES
@sankarchandraray as we both are new to steemit........can not see your help(f o l l o w) for me
OK DUDE...
Hey! I'm not an expert in maths, but i came up with this.
a) If i understand it right you need to create a function for f/g
f/g =
(-3x + 1)/(-5x + 6)=-1 * (3x - 1)/ -1 * (5x - 6)=(3x - 1)/(5x - 6)This is the simplest form i can get it to.
x can't be equal to 1.2, since then 5 * 1.2 = 6 and 6 - 6 = 0, and you can't divide by 0.
b) If I understand it right, I can answer with an expression
Avg. is: delta y/delta x, so (highest Y - lowest Y)/(highest X - lowest X) =
(k(h - 1) - k(-1))/(h -1 - (-1))=(k(h - 1) - k(-1))/h=(k(h - 1) -1)/hThis is the simplest form i can get it to.
h -1 - (-1)is H because:- (-1)is+1and-1 + 1is0, which we can ignore. H can't equal to zero is right as stated in the exercise.c) If I understand right I can answer with an expression
Same.
Avg. = delta Y / delta X =
(g(h) - g(0))/(h - 0)=(g(h) - g(0))/h=(g(h))/(h)g(0) = 0, this way we can ignore this, because: 0^2 = 0, 0*9 = 0
Sorry if I did something wrong English isn't my main language.
Legend
/means division-means subtraction*means multiplication+means adddeltameans it's a differential value (highest value - starting point)Let me know if this is what you want, or you can't understand this!