Assuming I win nothing when I lose a game the following will be my expected value of this discrete Bernoulli random variables
and assuming I only have one try.
for option A the E(x) = 0.910 + 00.1 = $9

for option c the E(x) = 500.1 + 00.9 = $5

for option C it is the chances of spontaneously combusts or not spontaneously combusts thus it it's Expected value is: 0.0000000011000000 + 99.9999...0 = $0,001

thus by pure expected value I would choose option A because it has the highest expected value. But lets say I can play any amount of games I want, then I will also choose option A for it has a stable and high chance of growth!.

so final answer overall, option A!