This is my entry @josegonzalito

Problem 1: (jumbled equations)
(2x3) + 5 = 11
(3x4) + 2 = 14
(5x13) + 4 = 69

Problem 2: (The sheep)
Let, r= number of ram
e= number of ewe
Total number of sheep head= (e+r)
But each sheep has four(4) hooves
Therefore, total hooves= (4e+4r)
And the number of ewe tongues is e, because every sheep has one tongue
Expressing this mathematically,

4e(r+e)^2=100
Dividing both sides by 4
e(e+r)^2=25
But 25 is a perfect square of a prime number (5), but e and r are non-negative integers
Thus, e= 1 and r=4 and total number of sheep heads=5

Therefore, there are five (5) sheep, of which only one (1) is an ewe